No, the engines HAVE to exist that way, its not theorhetical. Its:
RPM=(HP*5252)/RPM.

You say "what if it also makes 95ft-lbs all the way to 7500? Then:
HP=(TQ*RPM)/5252
Hp=(95*7500)/5252; HP=~136

You see? Then its PEAK HP is no longer 100! It no longer fits the example. It changed, all Im doing is using the exact variables you gave me to do some calculations. The big problem here is you guys are trying to boil it down to HP vs TQ. This really cant be done, the formula to FIND HP, includes RPM.


Ghost, my good buddy. Put that Cam on there and prove my point. Run a dyno before AND after, not only will you gain tq.. you will also gain power. Its so obvious it figuratively kicking you in the face:
HP=(TQ*RPM)/5252

Ok your drag engine that you build gets 100hp/100ft-lbs tq at 5252 rpm.
Now we put in your cam and gain 10ft-lbs tq.
HP=(TQ*RPM)/5252
HP=(110*5252)/5252; HP=110 OMG you gained power to! That must be how you moved down the track faster!
Torque is a FORCE, applying a force to something means nothing. Go outside and push on your house. Your applying a FORCE to it but doing NO work. As soon as that FORCE moves something then it is doing WORK (which horsepower measures).
You also CANNOT leave RPM out of the equation, trying to boil it down to HP vs TQ sounds nice but you can't do that and expect truely understand whats happening, all three variables are dependant on eachother.

Btw, I have read that article before and IMO reading an arguement between a few members isnt the best way to learn. Obviously one of them has got to be wrong and when their arguements are as long and somewhat convoluted as theirs were it gets very confusing.

 

Good catch. I should not have made the example have more HP. But what I said about looking at the peaks alone still holds true. I should have given an example of the Tq dropping off drastically instead of maintaining it through the rpm. But as far as you making the inference that the two cars...one making 100hp and 100 tq (at5252)and one making 100hp and 200 (at 2626) will tie is still wrong.

Lets look at what might be possible given tha parameters you have laid out.

engine 1: peaks at 100 both HP and Tq at 5252
but what about the rest of the rpm range?
2000 rpm = 25 ft/lbs 25x2000/5252= 9.5 HP
3000 rpm = 30 ft/lbs 30x3000/5252= 17.1 HP
4000 rpm = 60 ft/lbs 60x4000/5252= 45.7 HP
5252 rpm = 100 ft/lbs 100x5252/5252= 100 HP
6500 rpm = 50 ft/lbs 50x6500/5252= 61.9 HP

Now thats a peaky POS motor but it still is within the parameters you stated.

Now lets compare the other engine and keep it within the paremeters you stated of 100 hp and 200 tq at 2626 rpm

2000 rpm = 199 ft/lbs 199x2000/5252 = 75 hp
2626 rpm = 200 ft/lbs 200x2626/5252 = 100 HP
3500 rpm = 150 ft/lbs 150x3500/5252 = 99.96 HP
4500 rpm = 115 ft/lbs 115x4500/5252 = 98.53 HP
5500 rpm = 95 ft/lbs 95x5500/5252 = 99.48 hp
6500 rpm = 75 ft/lbs 75x6500/5252 = 92.8 hp


Its glaringly apparent that engine #2 will STOMP a mudhole in engine #1 one if they were in the same car with the same gearing and same weight. And we have stayed withing the constraints you set. Obvioulsy these are extreme examples. Like I said...looking at peaks alone really doesnt tell you much.

 

Alright, I see that we both have the right idea here, what you say is true. I was just going off of someone's question using the 2 cars assuming everything else was held equal.

 

so I guess diesel engines can factor into this too eh?

lots o torque, but no rpm

 

sorry but the car will run faster due to there being more tq witch= faster 60ft times there for u will run faster in the 1/4.it has nothing to do with hp and i know this for a fact becuase i get custom ground cams done all the time.oh an yes the engine made power at the same rpm level and had the same hp level but 30ft lbs of tq.just think if i had a big block that made 700hp and then a small block that made 700hp the big block will run faster in the 1/4 due to more tq.

 

yeah...I can see from your last post you obviously understand. I am with you on the "Tq without rpm means nothing". Thats definately true. This whole subject is hard to debate and think about while throwing around different parameters.

 

"oh an yes the engine made power at the same rpm level and had the same hp level but 30ft lbs of tq."

This statement is all that is needed to prove you wrong. Sorry man. But just look at the equation.

HP=(TQ*RPM)/5252

There is absolutely NO POSSIBLE WAY that you can change TQ without changing the HP number at the end of the equation. You might as well try to tell me that 1+3=1.

 

if i still had the damn dyno sheets i would show u them.