Gotta quick sub to amp wiring question
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Gotta quick sub to amp wiring question
Ok i gotta alpine amp thats
Alpine 3554 4ch amp. 50 watts x4 at 4 ohms
Now if i was to wire 1 10" to the amp that has a 4 ohm coil, how many watts would it see. Its going to b bridged, not wired to jus one strait channel
Alpine 3554 4ch amp. 50 watts x4 at 4 ohms
Now if i was to wire 1 10" to the amp that has a 4 ohm coil, how many watts would it see. Its going to b bridged, not wired to jus one strait channel
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Its a 10" bazooka with single voice coil. The single coil is 4 ohms. The amp does 50x4 in 4 ohms. Im going to wire the first 2 channels bridged like it says on the amp. How many watts would this b
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Originally posted by MDIFYTD
should be ~200
should be ~200
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if ur using a 4 channel amp u will get 100 of the bridged channel
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how do you figure?
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Ill say i go by His and Al's thoery of "Your getting sprayed" Doesnt matter what it is. Grandma in the 1982 LTD is gettin the bottle.
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Originally posted by stockls 15.4??what
if ur using a 4 channel amp u will get 100 of the bridged channel
if ur using a 4 channel amp u will get 100 of the bridged channel
I was going to say the same thing, but I don't know much. The way I see it the sub can only get power from 2 of the channels which is 100 watts.
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Ok so you have an amp that puts out 50w @4ohms.
Ohms law
P=V ²/R and V=IR
P=power, V=volts, R=resistance, I=current
We know that 50w=V²/4ohm or 200=V² or 14.1=V.
So now we know the Voltage we want to solve for the current across each channel. I=V/R or I=14.1/4 or I=3.53
So now that we know the current per channel we can plug it in to find out what the power output of combining two channels would be. P=I²R or P=7.06² * 4 or P=199.37 watts
Ohms law
P=V ²/R and V=IR
P=power, V=volts, R=resistance, I=current
We know that 50w=V²/4ohm or 200=V² or 14.1=V.
So now we know the Voltage we want to solve for the current across each channel. I=V/R or I=14.1/4 or I=3.53
So now that we know the current per channel we can plug it in to find out what the power output of combining two channels would be. P=I²R or P=7.06² * 4 or P=199.37 watts
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